STANDARD Chemistry Work Done in Isothermal Processes MCQ Question
The work done (in ergs) for the reversible expansion of one mole of an ideal gas from a volume of 10 L to 20 L at 25°C is
2.303 × 298 × 0.082 log 2
−298 × 10⁷ × 8.31 × 2.304 log 2
2.303 × 298 × 0.082 log 0.5
2.303 × 298 × 2 log 2
Correct Answer
Detailed Explanation
The work done in reversible isothermal expansion is given by w = −2.303nRT log(V₂/V₁). Substituting the values, we get w = −298 × 10⁷ × 8.31 × 2.303 log 2.
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