STANDARDChemistry-Thermodynamics
STANDARD Chemistry Work Done by Gases MCQ Question
Type: MCQ-numerical-Medium-Class 11
The work done during the expansion of a gas from 4 dm³ to 6 dm³ against a constant external pressure of 3 atm is (1 L atm = 101.32 J)
A
−6J
B
−608 J
C
+304 J
D
−304 J
Correct Answer
Option B
Detailed Explanation
Work done (W) is calculated using the formula W = −PΔV. Here, ΔV = (6 − 4) dm³ = 2 dm³ = 2 L. W = −3 atm × 2 L × 101.32 J/L atm = −608 J.
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