STANDARDChemistry-Thermodynamics
STANDARD Chemistry Isothermal Processes MCQ Question
Type: MCQ-numerical-Medium-Class 11
For an isothermal reversible expansion process, the value of q can be calculated by the expression
A
q = 2.303 nRT log V₂/V₁
B
q = -2.303 nRT log V₂/V₁
C
q = -nRT log V₂/V₁
D
q = -Pₑₓₚ nRT log V₂/V₁
Correct Answer
Option A
Detailed Explanation
In an isothermal reversible expansion, the heat exchanged q is given by q = 2.303 nRT log V₂/V₁, where V₂ and V₁ are the final and initial volumes respectively.
Found an issue with this question?
Related Questions
More from
Which of the following statements about enthalpy changes in thermodynamics is correct?
(general)Physics
What is the enthalpy change associated with the atomization of dihydrogen (H2)?
(general)Physics
For a strongly endothermic reaction, what is the expected value of the equilibrium constant K?
(general)Physics