STANDARDChemistry-Chemical Thermodynamics
STANDARD Chemistry Gibbs Free Energy MCQ Question
Type: MCQ-numerical-Medium-Class 11
For a reversible reaction at 298 K the equilibrium constant K is 200. What is the value of ΔG° at 298 K?
A
−13.13 kcal
B
−0.13 kcal
C
−3.158 kcal
D
−0.413 kcal
Correct Answer
Option C
Detailed Explanation
Using the formula ΔG° = −2.303 RT × log K, where R = 2 cal/mol·K and T = 298 K, we calculate ΔG° = −2.303 × 2 × 298 × log 200 = −3.158 kcal.
Found an issue with this question?
Related Questions
More from
Which of the following statements about enthalpy changes in thermodynamics is correct?
(general)Physics
What is the enthalpy change associated with the atomization of dihydrogen (H2)?
(general)Physics
For a strongly endothermic reaction, what is the expected value of the equilibrium constant K?
(general)Physics