STANDARDChemistry-Thermodynamics
STANDARD Chemistry First law of thermodynamics MCQ Question
Type: MCQ-numerical-Medium-Class 11
A gas is allowed to expand in a well insulated container against a constant external pressure of 2.5 atm from an initial volume of 2.50 L to a final volume of 4.50 L. The change in internal energy ΔU of the gas in joules will be
A
−500 J
B
−500 J
C
+500 J
D
1136.25 J
Correct Answer
Option B
Detailed Explanation
The work done is w = −PₑₓₜΔV = −2.5(4.50 − 2.50) = −5 L atm = −5 × 101.325 J = −506.625 J. Since the container is insulated, q = 0, hence, ΔU = w = −506.625 J.
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