Standard Books Chemistry Quantum Numbers MCQ Question with Solution

The orbital angular momentum for an electron revolving in an orbit is given by $\sqrt{l(l+1)} \frac{h}{2\pi}$ . This momentum for an s-electron will be given by

A

Zero

B

$\frac{h}{2\pi}$

C

$\sqrt{2} \cdot \frac{h}{2\pi}$

D

$\frac{1}{2} \cdot \frac{h}{2\pi}$

Correct Answer

Option A

Detailed Explanation

For s-electron, l = 0. Orbital angular momentum = $\sqrt{0(0+1)} \frac{h}{2\pi} = 0$ .

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