STANDARDChemistry-Atomic Structure

STANDARD Chemistry Isotopes MCQ Question

Type: MCQ-numerical-Medium-Class 11

The natural boron of atomic weight 10.81 is found to have two isotopes ¹⁰B and ¹¹B. The ratio of abundance of isotopes of natural boron should be

A

11 : 10

B

81 : 19

C

10 : 11

D

19 : 81

Correct Answer

Option D

Detailed Explanation

Let the abundance of ¹⁰B be x%. Then the abundance of ¹¹B is (100 - x)%. The atomic weight equation is 10.81 = (10x + 11(100 - x))/100. Solving for x gives the ratio 19:81.

Found an issue with this question?