STANDARD Chemistry Colligative Properties MCQ Question
Vapour pressure of a pure liquid X is 2 atm at 300 K. It is lowered to 1 atm on dissolving 1 g of Y in 20 g of liquid X. If molar mass of X is 200, what is the molar mass of Y?
20
50
100
200
Correct Answer
Detailed Explanation
Using the formula for relative lowering of vapour pressure: , we find the molar mass of Y by substituting the given values: .
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