STANDARD Chemistry Colligative Properties MCQ Question
1 g of solute (molar mass = 50 g mol⁻¹) is dissolved in 50 g of solvent and the elevation in boiling point is 1 K. The molal elevation constant of the solvent is
2
3
2.5
5
Correct Answer
Detailed Explanation
The molal elevation constant (K_b) is calculated using the formula ΔT_b = K_b × m, where m is the molality. Here, ΔT_b = 1 K, and m = (1/50) × 1000 = 20 mol/kg. Thus, K_b = 1/20 = 0.05 K kg/mol.
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