STANDARDChemistry-Oxidation and Reduction
STANDARD Chemistry Oxidation States MCQ Question
Type: MCQ-conceptual-Medium
The oxidation state of Sulphur in the anions SO₃²⁻, SO₄²⁻, S₂O₄²⁻, S₂O₆²⁻ is in the order of
A
SO₄²⁻ > S₂O₆²⁻ > S₂O₄²⁻ > SO₃²⁻
B
S₂O₆²⁻ > SO₃²⁻ > S₂O₄²⁻ > SO₄²⁻
C
SO₄²⁻ > S₂O₆²⁻ > SO₃²⁻ > S₂O₄²⁻
D
SO₃²⁻ > SO₄²⁻ > S₂O₄²⁻ > S₂O₆²⁻
Correct Answer
Option C
Detailed Explanation
SO₃²⁻ → x + (-6) = -2 ⇒ x = +4 SO₄²⁻ → x + (-8) = -2 ⇒ x = +6 S₂O₄²⁻ → 2x + (-8) = -2 ⇒ x = +3 S₂O₆²⁻ → 2x + (-12) = -2 ⇒ x = +5 Hence SO₄²⁻ > S₂O₆²⁻ > SO₃²⁻ > S₂O₄²⁻
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