STANDARDChemistry-Empirical Formula
STANDARD Chemistry Empirical and Molecular Formulas MCQ Question
Type: MCQ-numerical-Medium
An organic compound on analysis gave C = 54.2%, H = 9.2% by mass. Its empirical formula is
A
CHO₂
B
CH₂O
C
C₂H₈O
D
C₂H₄O
Correct Answer
Option D
Detailed Explanation
The empirical formula is determined by calculating the moles of each element and finding the simplest whole number ratio. For C: 54.2/12 = 4.5, H: 9.2/1 = 9.2, O: 36.6/16 = 2.3. The simplest ratio is 2:4:1, giving the empirical formula C₂H₄O.
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