STANDARD Chemistry Faraday's Laws MCQ Question
An electric charge of 5 Faradays is passed through three electrolytes AgNO₃, CuSO₄ and FeCl₃ solution. The grams of each metal liberated at cathode will be:
Ag = 10.8 g, Cu = 12.7 g, Fe = 1.11 g
Ag = 540 g, Cu = 367.5 g, Fe = 325 g
Ag = 108 g, Cu = 63.5 g, Fe = 56 g
Ag = 540 g, Cu = 158.8 g, Fe = 93.3 g
Correct Answer
Detailed Explanation
Using Faraday's laws, the mass of metal deposited is proportional to the charge passed. For 5 Faradays, Ag = 540 g, Cu = 158.8 g, Fe = 93.3 g are deposited.
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