STANDARD Chemistry Electrolysis MCQ Question
During electrolysis of a solution of AgNO₃, 9650 coulombs of charge is passed through the solution. What will be the mass of silver deposited on the cathode?
108 g
10.8 g
1.08 g
216 g
Correct Answer
Detailed Explanation
The mass of silver deposited is calculated using the formula: mass = (molar mass × charge) / (n × Faraday's constant). For Ag, n = 1, so mass = (108 × 9650) / 96500 = 10.8 g.
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