STANDARD Chemistry Oxidation States MCQ Question with Solution

The oxidation state of molybdenum in its oxo complex species [Mo₂O₄(C₂H₄)₂(H₂O₂)]²⁻ is

A

+2

B

+3

C

+4

D

+5

Option B

Oxidation number of Mo in [Mo₂O₄(C₂H₄)₂(H₂O₂)]²⁻ is calculated as 2x + 4(-2) + 0 + 0 = -2. Solving gives 2x - 8 = -2, hence x = +3.

Found an issue with this question?

What is the correct electronic configuration of the central atom in K₄[Fe(CN)₆] based on crystal field theory?

What is the term for the energy separation of d orbitals due to the presence of ligands in a specific geometry?

Which type of isomerism occurs in complexes containing ambidentate ligands?

How is the coordination number of a central atom or ion in a coordination entity determined?