STANDARD Chemistry Equilibrium Constant MCQ Question
For the following reaction: NO(g) + O₃(g) ⇌ NO₂(g) + O₂(g) The value of Kc is 8.2 × 10⁴. What will be the value of Kc for the reverse reaction?
8.2 × 10⁴
1 / 8.2 × 10⁴
(8.2 × 10⁴)²
√8.2 × 10⁴
Correct Answer
Detailed Explanation
The equilibrium constant for the reverse reaction is the reciprocal of the forward reaction. Therefore, Kc for the reverse reaction is 1 / 8.2 × 10⁴.
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