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STANDARDChemistry-Chemical Equilibrium

STANDARD Chemistry Acid-Base Equilibria MCQ Question

Type: MCQ-numerical-Medium

The degree of ionization of an acid HA is 0.00001 at 0.1 M concentration, Its dissociation constant will be

A

10⁻⁹

B

10⁻¹¹

C

10⁻⁸

D

10⁻⁷

Correct Answer

Option B

Detailed Explanation

The dissociation constant KaK_a is calculated using the formula Ka=Cα2K_a = C\alpha^2. Given α=10−5\alpha = 10^{-5} and C=0.1C = 0.1, we find Ka=0.1imes(10−5)2=10−11K_a = 0.1 imes (10^{-5})^2 = 10^{-11}.

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