STANDARDChemistry-Chemical Equilibrium

STANDARD Chemistry Acid-Base Equilibria MCQ Question

Type: MCQ-numerical-Medium

What is the percentage dissociation of 0.1 M solution of acetic acid? (Kₐ = 10⁻⁵)

A

10%

B

100%

C

1%

D

0.01%

Correct Answer

Option C

Detailed Explanation

The percentage dissociation is calculated using \alpha = \sqrt{ rac{K_a}{C}}. Substituting Ka=105K_a = 10^{-5} and C=0.1C = 0.1, we get \alpha = \sqrt{ rac{10^{-5}}{0.1}} = 10^{-2}. Therefore, the percentage dissociation is 102imes100=1%10^{-2} imes 100 = 1\%.

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