STANDARD Chemistry Isotopes MCQ Question
The natural boron of atomic weight 10.81 is found to have two isotopes ¹⁰B and ¹¹B. The ratio of abundance of isotopes of natural boron should be
11 : 10
81 : 19
10 : 11
19 : 81
Correct Answer
Detailed Explanation
Let the abundance of ¹⁰B be x%. Then the abundance of ¹¹B is (100 - x)%. The atomic weight equation is 10.81 = (10x + 11(100 - x))/100. Solving for x gives the ratio 19:81.
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