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STANDARD Chemistry Hydrogen Spectrum MCQ Question

Type: MCQ-conceptual-Medium-Class 11

The wavelength of radiation emitted is λ₀ when an electron jumps from the third to second orbit of hydrogen atom. For the electron jumping from the fourth to the second orbit of the hydrogen atom, the wavelength of radiation emitted will be

A

(16/25) λ₀

B

(20/27) λ₀

C

(27/20) λ₀

D

(25/16) λ₀

Correct Answer

Option B

Detailed Explanation

Using the formula for wavelength λ/λ₀ = (1/n₁² - 1/n₂²) / (1/2² - 1/3²), we find λ = (20/27) λ₀ for the transition from n=4 to n=2.

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