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RE-NEET2024Physics-Young's Double Slit Experiment

RE-NEET 2024 Physics Young's Double Slit Experiment MCQ Question

Type: MCQ-numerical-Medium-Class 12

Two slits in Young’s double slit experiment are 1.5 mm apart and the screen is placed at a distance of 1 m from the slits. If the wavelength of light used is 600 × 10⁻⁹ m then the fringe separation is

A

4 × 10⁻⁵ m

B

9 × 10⁻⁸ m

C

4 × 10⁻⁷ m

D

4 × 10⁻⁴ m

Correct Answer

Option D

Detailed Explanation

Topic: Young’s Double Slit Experiment Difficulty: 🟡 Medium

✅ Ans: D — 4×10−4 m4\times10^{-4}\,m

Fringe separation:

β=λDd\beta=\frac{\lambda D}{d}

(MedicNEET)

Given:

λ=600×10−9m,D=1m,d=1.5mm=1.5×10−3m\lambda=600\times10^{-9}m,\quad D=1m,\quad d=1.5mm=1.5\times10^{-3}m β=600×10−9×11.5×10−3\beta=\frac{600\times10^{-9}\times1}{1.5\times10^{-3}} β=4×10−4m\boxed{\beta=4\times10^{-4}m}

❌ Why other options are wrong?

They result from incorrect conversion of mm to m or incorrect substitution.

📌 NCERT: β=λDd\beta=\frac{\lambda D}{d}

🧠 NEET Trick: Fringe width = λD/d → λ and D on top, d below.

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