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RE-NEET2026Physics-Modern Physics

RE-NEET 2026 Physics Photon and Electron Momentum MCQ Question

Type: MCQ-numerical-Hard-Class 12

A photon and an electron, each of 20 eV energy, move in free space. The ratio of linear momentum of electron pₑ to that of photon p_ph is: (Take speed of light = 3×10⁸ ms⁻¹, charge of electron = -1.6×10⁻¹⁹ C and mass of electron = 9×10⁻³¹ kg)

A

1/250

B

225

C

275

D

2/450

Correct Answer

Option B

Detailed Explanation

✅ Ans: 2 → 225

Key Concept:

For photon:

pph=Ecp_{ph}=\frac{E}{c}

For electron:

pe=2meEp_e=\sqrt{2m_eE}

Therefore,

pepph=2meE cE=c2meE\frac{p_e}{p_{ph}} =\frac{\sqrt{2m_eE}\,c}{E} =c\sqrt{\frac{2m_e}{E}}

For E=20 eVE=20\,eV:

pepph≈225\boxed{\frac{p_e}{p_{ph}}\approx225}

❌ Why other options are wrong?

  • 1/250 ❌ → ratio is inverted
  • 275 ❌ → incorrect numerical substitution
  • 2/2450 ❌ → incorrect momentum relation

📌 NCERT: “The momentum of a photon is p=h/λ=E/cp=h/\lambda=E/c.”

🧠 NEET Trick: Same energy → photon momentum =E/c=E/c, electron momentum =2mE=\sqrt{2mE}.

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