RE-NEET2024Physics-Rotational Motion

RE-NEET 2024 Physics Moment of Inertia MCQ Question

Type: MCQ-numerical-Hard-Class 11

The radius of gyration of a solid sphere of mass 5 kg about XY is 5 m as shown in figure. The radius of the sphere 5x7\frac{5x}{\sqrt{7}} m, then the value of x is:

Question diagram
A

5

B

2\sqrt{2}

C

3\sqrt{3}

D

5\sqrt{5}

Correct Answer

Option D

Detailed Explanation

The radius of gyration k is related to the radius R of the sphere by the formula k = R/5\sqrt{5}. Solving for x in 5x7=R/5\frac{5x}{\sqrt{7}} = R/\sqrt{5} gives x = 5\sqrt{5}.

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