RE-NEET 2026 Physics Nuclear Reactions MCQ Question
Consider the following nuclear reaction: ²³⁸U → ²³⁴Th + ⁴He. Take masses of ²³⁸U, ²³⁴Th and ⁴He as 238.050 u, 234.043 u and 4.003 u, respectively. The Q value for the reaction, in keV, is: [Given: 1 u = 931.5 MeV c⁻²]
3730
3736
3740
3726
Correct Answer
Detailed Explanation
The Q value is calculated using the mass defect, which is the difference in mass before and after the reaction, multiplied by 931.5 MeV/u to convert to energy.
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