RE-NEET 2024 Chemistry Molarity MCQ Question
The amount of glucose required to prepare 250 mL of M/20 aqueous solution is: (Molar mass of glucose: 180 g mol⁻¹)
2.25 g
4.5 g
0.44 g
1.125 g
Correct Answer
Detailed Explanation
The molarity (M) is given as M/20, which means 1/20 M. For 250 mL (0.25 L), the moles of glucose required are (1/20) × 0.25 = 0.0125 moles. The mass of glucose is 0.0125 × 180 = 2.25 g.
Found an issue with this question?
Related Questions
More from Solutions
A 5% solution (by mass) of cane sugar in water has freezing point of 271 K and freezing point of pure water is 273.15 K. The freezing point of a 5% so...
Elevation in the boiling point for 1 molal solution of glucose is 2 K. The depression in the freezing point for 2 molal solution of glucose in the sam...
What amount of CaCl₂ (i = 2.47) is dissolved in 2 litres of water so that its osmotic pressure is 0.5 atm at 27°C?
More from 2024
Which of the following factors are favourable for the formation of oxyhaemoglobin in alveoli?
On heating, some solid substances change from solid to vapour state without passing through liquid state. The technique used for the purification of s...