RE-NEET 2026 Chemistry Combustion Reactions MCQ Question

The molar mass of n-butane is

$M(\text{C}_4\text{H}_{10}) = 4(12) + 10(1) = 58\ \text{g mol}^{-1}$

so 116 g is 2 mol. Complete combustion gives

$\text{C}_4\text{H}_{10} + \tfrac{13}{2}\text{O}_2 \rightarrow 4\text{CO}_2 + 5\text{H}_2\text{O}$

4 mol of $\text{CO}_2$ per mol of butane, so $2 \times 4 = 8$ mol, and

$m = 8 \times 44 = 352\ \text{g}$

176 g is the answer for 1 mol of butane (58 g), and 322 g and 362 g follow from a wrong molar mass for butane or for $\text{CO}_2$.