RE-NEET 2024 Chemistry Molarity MCQ Question
The amount of glucose required to prepare 250 mL of M/20 aqueous solution is: (Molar mass of glucose: 180 g mol⁻¹)
2.25 g
4.5 g
0.44 g
1.125 g
Correct Answer
Detailed Explanation
The molarity (M) is given as M/20, which means 1/20 M. For 250 mL (0.25 L), the moles of glucose required are (1/20) × 0.25 = 0.0125 moles. The mass of glucose is 0.0125 × 180 = 2.25 g.
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