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RE-NEET2026Chemistry-Aldehydes, Ketones & Carboxylic Acids

RE-NEET 2026 Chemistry Haloform Reaction MCQ Question

Type: MCQ-diagram based-Medium-Class 11

For the following reaction sequence, choose the correct option

Question diagram
A

P and Q are aromatic compounds.

B

If P gives a carboxylic acid on acidification, Q gives a poisonous gas on exposure to air and light.

C

Both P and Q are carbonyl compounds.

D

If P is the sodium salt of a carboxylic acid, Q is a primary alcohol.

Correct Answer

Option B

Detailed Explanation

Chemistry | Haloform Reaction

Topic: Aldehydes, Ketones & Carboxylic Acids Difficulty: 🟡 Medium

✅ Ans: B

Step 1: Friedel–Crafts acylation

C6H6→CH3COCl/AlCl3C6H5COCH3C_6H_6 \xrightarrow{CH_3COCl/AlCl_3} C_6H_5COCH_3

Product = acetophenone

Step 2: NaOClNaOCl → Haloform reaction

Methyl ketone gives:

C6H5COCH3→NaOClC6H5COONa+CHCl3C_6H_5COCH_3 \xrightarrow{NaOCl} C_6H_5COONa + CHCl_3

So,

  • P = Sodium benzoate → on acidification gives benzoic acid
  • Q = Chloroform (CHCl3)(CHCl_3) → on exposure to air & light can form phosgene (COCl2)(COCl_2), a poisonous gas.
B is correct\boxed{\text{B is correct}}

❌ Other options

  • A ❌ → P is a salt, not an aromatic compound.
  • C ❌ → P is not a carbonyl compound.
  • D ❌ → Q is chloroform, not a primary alcohol.

📌 NCERT: Methyl ketones give haloform reaction with halogen/hypohalite, producing a carboxylate salt and haloform.

🧠 NEET Trick: CH3CO−R+NaOCl→RCOONa+CHCl3CH_3CO-R + NaOCl \rightarrow RCOONa + CHCl_3 → methyl ketone → carboxylate + chloroform.

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