Zoology-Natural Selection
NEET Zoology Natural Selection MCQ Question
Type: MCQ-numerical-Easy-Class 12
If the frequency of allele A in a population is 0.6, what is the expected frequency of heterozygous individuals (Aa) under Hardy-Weinberg equilibrium?
A
0.24
B
0.36
C
0.48
D
0.16
Correct Answer
Option C
Detailed Explanation
Using the Hardy-Weinberg equation p^2 + 2pq + q^2 = 1, where p = 0.6 and q = 0.4, the frequency of Aa is 2pq = 2(0.6)(0.4) = 0.48.
Found an issue with this question?