Physics-Interference
NEET Physics Interference MCQ Question
Type: MCQ-numerical-Hard-Class 12
In Young's Double Slit Experiment, the separation between the slits is 0.025 mm, the distance to the screen is 5 cm, and the wavelength of light used is 5 × 10⁻⁵ cm. What is the distance between the central maximum and the second-order bright fringe?
A
0.02 cm
B
0.04 cm
C
0.06 cm
D
0.08 cm
Correct Answer
Option B
Detailed Explanation
The distance x for the nth order bright fringe is given by x = nλD/d. For n = 2, x = 2 × 5 × 10⁻⁵ cm × 5 cm / 0.025 mm = 0.04 cm.
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