Physics-Interference
NEET Physics Interference MCQ Question
Type: MCQ-numerical-Hard-Class 12
In Young's double-slit experiment, if the distance between the slits (d) is 0.025 mm, the distance from the slits to the screen (D) is 5 cm, and the wavelength of light (λ) is 5 × 10^-5 cm, what is the distance between the central bright fringe and the first-order bright fringe on the screen?
A
0.1 cm
B
0.05 cm
C
0.2 cm
D
0.5 cm
Correct Answer
Option A
Detailed Explanation
The formula x = nDλ/d is used to find the distance between fringes. Substituting n=1, D=5 cm, λ=5×10^-5 cm, and d=0.025 mm (0.0025 cm), the distance is x = 1×5×5×10^-5/0.0025 = 0.1 cm.
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