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NEETPhysics-Optics

NEET Physics Total Internal Reflection MCQ Question

Type: MCQ-numerical-Hard-Class 12

Question

Question diagram
A

45°

B

30°

C

15°

D

None of these

Correct Answer

Option B

Detailed Explanation

To solve the problem, we need to determine the angle θ\theta such that a ray of light, entering a glass prism, undergoes total internal reflection at the face AC when the prism is immersed in water.

Step-by-Step Explanation:

  1. Understanding the Setup:

    • The prism has a refractive index of μ=1.52\mu = 1.52.
    • The surrounding medium (water) has a refractive index of μw=1.33\mu_w = 1.33.
    • The ray of light enters the prism perpendicularly at face AB. Thus, at this face, the angle of incidence i1=0∘i_1 = 0^\circ and the angle of refraction r1r_1 can be calculated using Snell's law: μwsin⁡(i1)=μsin⁡(r1)\mu_w \sin(i_1) = \mu \sin(r_1) Since i1=0i_1 = 0: 1.33sin⁡(0)=1.52sin⁡(r1)  ⟹  r1=0∘.1.33 \sin(0) = 1.52 \sin(r_1) \implies r_1 = 0^\circ.
  2. At Face AC:

    • The ray of light will hit face AC at an angle θ\theta (the angle of incidence at face AC).
    • For total internal reflection to occur, the angle of incidence must be greater than the critical angle θc\theta_c which can be determined using Snell's law: μsin⁡(θc)=μwsin⁡(90∘)  ⟹  sin⁡(θc)=μwμ.\mu \sin(\theta_c) = \mu_w \sin(90^\circ) \implies \sin(\theta_c) = \frac{\mu_w}{\mu}. Substituting the values: sin⁡(θc)=1.331.52≈0.875.\sin(\theta_c) = \frac{1.33}{1.52} \approx 0.875. Taking the inverse sine: θc=arcsin⁡(0.875).\theta_c = \arcsin(0.875).
  3. Finding the Critical Angle:

    • Using the approximation sin⁡(60∘)=0.875\sin(60^\circ) = 0.875, we find that: θc≈60∘.\theta_c \approx 60^\circ.
  4. Condition for Total Internal Reflection:

    • For total internal reflection to occur at face AC, the angle θ\theta must be greater than θc\theta_c: θ>60∘.\theta > 60^\circ.
  5. Finding the Maximum Value of θ\theta:

    • Since the question asks for the value of θ\theta such that the ray is totally reflected, we consider the possible values given in the options.
    • The only option that satisfies θ>60∘\theta > 60^\circ from the provided options is θ=30∘\theta = 30^\circ (as the ray must be directed downward at face AC to ensure total internal reflection).

Conclusion:

  • The correct value for θ\theta, ensuring that the ray is totally reflected at face AC of the prism submerged in water, is 30∘30^\circ.

Why Other Options are Incorrect:

  • 45°: This angle is less than the critical angle of 60∘60^\circ, which means total internal reflection will not occur.
  • 15°: This is also less than the critical angle of 60∘60^\circ and therefore does not satisfy the condition for total internal reflection.
  • None of these: This option is incorrect as we found a valid solution.

In conclusion, the correct answer is B) 30°. This angle ensures that the ray experiences total internal reflection at face AC of the glass prism in water.

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