NEET Physics Photoelectric Effect MCQ Question
Light of two different frequencies whose photons has energies 1 eV and 2.5 eV respectively, successively illuminates a metal of work function 0.5 eV. The ratio of maximum kinetic energy of the emitted electron will be
1 : 5
1 : 4
3 : 2
1 : 1
Correct Answer
Detailed Explanation
The kinetic energy of emitted electrons is given by KE = hf - φ. For the two frequencies, KE ratios are (1-0.5) : (2.5-0.5) = 0.5 : 2 = 1 : 4.
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