NEET2025Physics-Optics
NEET 2025 Physics Microscopes MCQ Question
Type: MCQ-numerical-Easy-Class 12
A microscope has an objective of focal length 2 cm, eyepiece of focal length 4 cm and the tube length of 40 cm. If the distance of distinct vision of eye is 25 cm, the magnification in the microscope is
A
100
B
125
C
150
D
250
Correct Answer
Option B
Detailed Explanation
The magnification of a compound microscope is given by the formula M = (L/f₀) × (D/fₑ), where L is the tube length, f₀ is the focal length of the objective, D is the distance of distinct vision, and fₑ is the focal length of the eyepiece. Substituting the given values, M = (40/2) × (25/4) = 125.
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