NEET Physics Nuclear Fission MCQ Question
If the average energy released per fission of 239 94 Pu is 180 MeV, approximately how much energy (in MeV) would be released if 2 kg of 239 94 Pu were completely fissioned?
52 × 10^26 MeV
6.02 × 10^24 MeV
08 × 10^25 MeV
61 × 10^27 MeV
Correct Answer
Detailed Explanation
Using the given data, the number of atoms in 2 kg of 239 94 Pu can be calculated using Avogadro's number, leading to the total energy released being 4.52 × 10^26 MeV.
Found an issue with this question?
Related Questions
More from Nuclear Fission
More from
Which of the following statements about the mass-energy relation and nuclear density is correct?
Which of the following statements regarding the mass-energy relation and nuclear binding energy is correct?
Match Column-I with Column-II. Column-I Column-II (a) Mass defect (i) Binding energy per nucleon (b) 16 O nucleus (ii) Energy associated wit...