Physics-Nuclear Fission
NEET Physics Nuclear Fission MCQ Question
Type: MCQ-numerical-Medium-Class 12
If 1 kg of pure 239Pu undergoes complete nuclear fission, approximately how much energy, in joules, is released?
A
7.54 × 10^13 J
B
61 × 10^13 J
C
44 × 10^14 J
D
32 × 10^14 J
Correct Answer
Option A
Detailed Explanation
The energy released per fission of 239Pu is 180 MeV. With Avogadro's number, we calculate the number of fissions in 1 kg and convert MeV to joules using 1 MeV = 1.6 × 10^-13 J.
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