NEET Physics Mass-Energy Relation MCQ Question with Solution

If a nucleus has a mass defect $\Delta M$ of 0.01 u, what is the binding energy $\Delta E_b$ of this nucleus in MeV? $(1 \text{ u} = 931.5 \text{ MeV/c}^2)$

A

9.315 MeV

B

0.09315 MeV

C

93.15 MeV

D

931.5 MeV

Correct Answer

Option A

Detailed Explanation

Using Einstein’s mass-energy relation $\Delta E_b = \Delta M c^2$ , and given $\Delta M = 0.01 \text{ u}$ , the binding energy is $0.01 \times 931.5 \text{ MeV} = 9.315 \text{ MeV}$ .

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