NEET Physics Mass-Energy Relation MCQ Question
If the mass defect of a nucleus is 0.13000 u, calculate the binding energy of the nucleus in MeV. (1 u = 931.5 MeV/c²)
121.1 MeV
121.5 MeV
122.0 MeV
122.5 MeV
Correct Answer
Detailed Explanation
The binding energy ΔE_b can be calculated using the mass-energy relation ΔE_b = ΔM * c², where ΔM is the mass defect. Given ΔM = 0.13000 u and 1 u = 931.5 MeV/c², the binding energy is ΔE_b = 0.13000 * 931.5 MeV = 121.5 MeV.
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