NEET Physics Magnetic Force on Current MCQ Question
Two very long, straight, parallel conductors carry equal currents of 5 A in opposite directions and are placed 1 meter apart in vacuum. What is the magnitude of the magnetic force per unit length experienced by each conductor?
2 × 10^-7 N/m
4 × 10^-7 N/m
5 × 10^-7 N/m
10 × 10^-7 N/m
Correct Answer
Detailed Explanation
The magnetic force per unit length between two parallel conductors is given by F/L = (μ0 * I1 * I2) / (2π * d). Substituting μ0 = 4π × 10^-7 N/A², I1 = I2 = 5 A, and d = 1 m, we get F/L = 4 × 10^-7 N/m.
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