NEET Physics Magnetic Force on Current MCQ Question
Two long parallel conductors a and b are separated by a distance d and carry currents I_a and I_b respectively. If I_a = 5 A, I_b = 3 A, and d = 0.2 m, what is the magnitude of the force per meter experienced by conductor b due to conductor a?
0 × 10⁻⁶ N/m
5 × 10⁻⁶ N/m
7.5 × 10⁻⁶ N/m
6.0 × 10⁻⁶ N/m
Correct Answer
Detailed Explanation
The formula for the force per unit length between two parallel conductors is F/L = (μ₀/2π) × (I_a × I_b) / d. Substituting the values gives F/L = (4π × 10⁻⁷ / 2π) × (5 × 3) / 0.2 = 6.0 × 10⁻⁶ N/m.
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