NEET Physics Magnetic Force on Current MCQ Question
A straight conductor of length 0.5 m carries a current of 12 A and is placed in a uniform magnetic field of 0.2 T. If the conductor makes an angle of 60º with the direction of the magnetic field, what is the magnitude of the magnetic force acting on the conductor?
1.04 N
1.20 N
1.04 T
1.20 T
Correct Answer
Detailed Explanation
The magnetic force on a current-carrying conductor in a magnetic field is given by F = I l B sin(θ). Substituting I = 12 A, l = 0.5 m, B = 0.2 T, and θ = 60º, we find F = 12 * 0.5 * 0.2 * sin(60º) = 1.04 N.
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