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Physics-Biot-Savart Law

NEET Physics Biot-Savart Law MCQ Question

Type: MCQ-numerical-Hard-Class 12

A current element I d l produces a magnetic field dB at a point P, located at a distance r from the element, with an angle θ between the element and the line joining the element to P. If μ0 = 4π × 10^-7 T m A^-1 and the current I is 3 A, what is the magnitude of dB if d l = 0.2 m, r = 0.5 m, and θ = 90°?

A

2 × 10^-7 T

B

4 × 10^-7 T

C

8 × 10^-7 T

D

6.0 × 10^-7 T

Correct Answer

Option B

Detailed Explanation

Using the Biot-Savart Law formula dB = (μ0/4π) * (I d l sin θ) / r^2, plug in the values: (10^-7 T m A^-1) * (3 A * 0.2 m * 1) / (0.5 m)^2 = 2.4 × 10^-7 T.

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