NEET Physics Bar Magnet MCQ Question
A short bar magnet of magnetic moment 5.25 × 10^-2 J T^-1 is placed with its axis perpendicular to the earth’s field direction. If the magnitude of the earth’s field at the place is 0.42 G, what is the distance from the center of the magnet on its normal bisector where the resultant field is inclined at 45° with the earth’s field?
0.15 m
0.25 m
0.35 m
0.45 m
Correct Answer
Detailed Explanation
Using the formula for the resultant field on the normal bisector of a short bar magnet and equating it to the condition for 45° inclination with earth's field, the distance can be calculated.
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