Physics-(general)
NEET Physics (general) MCQ Question
Type: MCQ-numerical-Hard-Class 12
Given a spherometer with a side of the equilateral triangle l = 3 cm and a measured sagitta h = 0.2 cm, calculate the radius of curvature R of the spherical surface.
A
23.05 cm
B
12.75 cm
C
18.45 cm
D
30.15 cm
Correct Answer
Option A
Detailed Explanation
Using the formula R = (l^2 / 6h) + (h / 2), where l = 3 cm and h = 0.2 cm, we find R = 23.05 cm.
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