Physics-(general)
NEET Physics (general) MCQ Question
Type: MCQ-numerical-Easy-Class 12
Using a spherometer, if the distance between any two legs is 6 cm and the sagitta is 0.5 cm, what is the radius of curvature of the spherical surface?
A
18.75 cm
B
15.25 cm
C
12.00 cm
D
10.50 cm
Correct Answer
Option A
Detailed Explanation
Using the formula R = (l^2 / 6h) + (h / 2), where l = 6 cm and h = 0.5 cm, the radius of curvature R is calculated as 18.75 cm.
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