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Physics-(general)

NEET Physics (general) MCQ Question

Type: MCQ-numerical-Hard-Class 12

If the radius of the base circle of a spherometer is 3 cm and the measured sagitta is 0.5 cm, calculate the radius of curvature of the spherical surface. Use the formula r2=h(2R−h)r^2 = h (2R - h) where RR is the radius of curvature, rr is the radius of the base circle, and hh is the sagitta.

A

9.75 cm

B

12.00 cm

C

18.75 cm

D

15.00 cm

Correct Answer

Option A

Detailed Explanation

Using the formula r2=h(2R−h)r^2 = h (2R - h), where r=3r = 3 cm and h=0.5h = 0.5 cm, solve for RR. This gives 9=0.5(2R−0.5)9 = 0.5(2R - 0.5), solving this gives R=9.75R = 9.75 cm.

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