NEET Physics (general) Match the Following Question
Match Column-I with Column-II.
Column-I Column-II (a) Corrected height of block (i) π V 2 –63 D h (b) Internal volume of the beaker (ii) h o – ( ± e ) (c) Mean measured depth of beaker (iii) 123 o hhh h ++ = 3 (d) Density of the given block (iv) m ==... V ρ –3 kg m
Choose the correct matching:
a-ii, b-i, c-iii, d-iv
a-iii, b-ii, c-i, d-iv
a-iv, b-iii, c-ii, d-i
a-i, b-iv, c-iii, d-ii
Correct Answer
Detailed Explanation
The corrected height of the block is calculated using the formula h = h o – ( ± e ). The internal volume of the beaker is given by the equation π V 2 –63 D h. The mean measured depth of the beaker is represented by the expression 123 o hhh h ++ = 3. The density of the block is calculated using the formula m ==... V ρ –3 kg m.
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