NEET Physics Properties of Electromagnetic Waves MCQ Question
The magnetic field of a plane electromagnetic wave is given by: B⃗ = 2×10⁻⁸ sin(0.5×10³x + 1.5×10¹¹t)ĵT. The amplitude of the electric field would be:
6 Vm⁻¹ along x-axis
3 Vm⁻¹ along z-axis
6 Vm⁻¹ along z-axis
2 × 10⁸ Vm⁻¹ along z-axis
Correct Answer
Detailed Explanation
The amplitude of the electric field E is related to the magnetic field B by E = cB, where c is the speed of light. Here, E = 3 × 10⁸ m/s × 2 × 10⁻⁸ T = 6 Vm⁻¹.
Found an issue with this question?
Related Questions
More from Electromagnetic Waves
More from
The equivalent inductance of two inductors is 2.4 H when connected in parallel and 10 H when connected in series. What is the value of inductances of ...
Which of the following types of electromagnetic waves was discovered last by the end of the nineteenth century?
Which of the following types of electromagnetic waves has the longest wavelength?