MarksRiser
MarksRiser
NEET2025Physics-Electromagnetism

NEET 2025 Physics Motion of Charged Particles MCQ Question

Type: MCQ-numerical-Medium-Class 12

Question

Question diagram
A

A

B

B

C

C

D

D

Correct Answer

Option B

Detailed Explanation

🧠 Explanation

For the electron to not deflect, the electric and magnetic forces must be equal and opposite:

qE=qvBqE=qvB

Therefore,

E=vBE=vB

Given:

v=c100=3Ɨ108100=3Ɨ106Ā m/sv=\frac{c}{100}=\frac{3\times10^8}{100} =3\times10^6\ \text{m/s}

and

B=9Ɨ10āˆ’4Ā TB=9\times10^{-4}\ \text{T}

So,

E=(3Ɨ106)(9Ɨ10āˆ’4)E=(3\times10^6)(9\times10^{-4}) E=27Ɨ102Ā V/m\boxed{E=27\times10^2\ \text{V/m}}

Since the electric force must oppose the magnetic force, Eāƒ—\vec E is perpendicular to Bāƒ—\vec B.

āœ… Answer: (B)

Eāƒ—āŠ„Bāƒ—,E=27Ɨ102Ā V/m\boxed{\vec E\perp\vec B,\quad E=27\times10^2\ \text{V/m}}

⚔ Quick Trick:

E=vB\boxed{E=vB}

For no deflection → electric force = magnetic force.

Found an issue with this question?