Physics-Motional EMF
NEET Physics Motional EMF MCQ Question
Type: MCQ-numerical-Easy-Class 12
A horizontal straight wire 10 m long is falling at right angles to the horizontal component of the Earth's magnetic field, which is 0.30 x 10^-4 Wb/m². If the wire moves at a speed of 5.0 m/s, what is the instantaneous value of the emf induced in the wire?
A
0.15 mV
B
5 mV
C
15 mV
D
150 mV
Correct Answer
Option C
Detailed Explanation
The induced emf (ε) is calculated using the formula ε = B * l * v, where B is the magnetic field, l is the length of the wire, and v is the velocity. Substituting the given values: ε = 0.30 x 10^-4 Wb/m² * 10 m * 5.0 m/s = 15 mV.
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