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Physics-Motional EMF

NEET Physics Motional EMF MCQ Question

Type: MCQ-numerical-Easy-Class 12

A horizontal straight wire 10 m long extends from east to west and falls with a speed of 5.0 m/s at right angles to the horizontal component of the earth’s magnetic field, which is 0.30 × 10^-4 Wb/m². What is the instantaneous value of the emf induced in the wire?

A

5 mV

B

0.15 mV

C

15 mV

D

0.015 mV

Correct Answer

Option A

Detailed Explanation

The induced emf is calculated using the formula emf = B * l * v, where B is the magnetic field, l is the length of the wire, and v is the velocity. Substituting the values, emf = 0.30 × 10^-4 Wb/m² * 10 m * 5.0 m/s = 1.5 mV.

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